The only reason why I know the answer to this is that I've read discussions on this subject, I'm not saying any of this is obvious...
...but it's not possible to run Linux binaries under OSX because of the binary interface, which includes the work the linker does, the functions, libraries, and the format of the executables. OS X only supports its own binary format ("Mach-0") for executable, and Apple doesn't have the linux "emulation" that is, as you mention, in many other BSD variation to make the linux executable thinks it's running a normal linux.
btw, OS X has a significantly modified BSD, with they have their own versions of gcc and file system locations, which probably complicates the matter.
> -----Original Message-----
> From: Alan Jones
>
> OS X is based on a BSD if I recall. A few of the BSDs have support for
> running linux binaries. I believe it's a kernel component and seeing
> Apple have decided to make the kernel source available for the x86
> architecture again I'd imagine that even if it's not in the standard
> kernel it would be possible to port it relatively easily.
>
> On 8/28/06, Luc-Eric Rousseau <lucer(at)softimage.com> wrote:
> > why would this be possible at all, OS X isn't based
> > on linux. you'd have more chance running XSI Windows
> > under Wine for XSI.
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