Re: Bad Operator Update
| Date : Thu, 14 Sep 2006 10:17:29 +0200 |
| To : XSI(at)Softimage.COM |
| From : Guy Rabiller <guy(at)alamaison.fr> |
| Subject : Re: Bad Operator Update |
They are ok, as being parameters, any change will be notified to the operator.
String parameters can be 'connected' to an operator.
For exemple when you use a string parameter for file path name used by an operator to load datas.
Any change to the parameter will trigger operator evalulation.
On a side note, unfortunately, string parameters are not animatable yet. It has been a requested for long a time. -- guy rabiller | 3d technical director (at) LaMaison
Nick a écrit :
string parameters?
On 9/14/06, *Guy Rabiller* <guy(at)alamaison.fr <mailto:guy(at)alamaison.fr>> wrote:
> ../.. So it's approprate for cases when you have > some noise function based on time, for example.
or when writing to/reading from disk.
Basicaly, this means that something changes without the Operator beeing notified.
And what changed in those cases ?
Time. And Time only. And Time wasn't 'connected' as an input of the Operator.
So rather than to toggle the 'always evaluate' flag, better 'connect' the Time factor to your operator, meaning adding a parameter with an expression such as Fc.
Now the Time value is 'connected' and your Operator will be properly updated, every frame.
May be I'm missing something, but this 'always evaluate' flag should disappear. It gives wrong habits and it is against the lazy evaluation mechanism. It should never has been exposed at first.
What kind of value, except for Time, could affect an Operator wich would need the 'always evaluate' flag to be turned on ?
What kind of value wich cannot be 'connected' to an Operator through parameter expression or other type of input ?
-- guy rabiller | 3d technical director (at) LaMaison
Luc-Eric Rousseau a écrit : > right - in an operator architecture, you can't assume the input is the same object as the input, even you made that connection yourself. > > The system is always free to replace either input or output with a cached buffer, for performance purpose, and if often does. > > The 'always evaluate' flag should rarely be used, and any use of it should be looked at carefully. It's meant to be used when your operator changes its result for each frame, even if there are no parameters animated, and the input is not changing. So it's approprate for cases when you have some noise function based on time, for example. > > > >> -----Original Message----- >> From: Helge Mathee >> >> >> No I don't. >> >> When you create a scripted op on let's say the kinematics.local of an >> objects, >> the scop contains two ports. One called something like Inlocal and one >> called Out. >> >> To make sure the evaluation is done correctly, you'll have to use the >> transform coming from the input port, not the one from the >> output port, >> as you are WRITING to the outputport, and READING from the input one. >> >> example: >> >> var xf = Inlocal.value.transform; >> var pos = XSIMath.CreateVector3(); >> pos.Set(10,0,0); >> xf.SetTranslation(pos); >> Out.value.transform = xf; >> >> cheers! >> >> -----Original Message----- >> From: owner-xsi(at)Softimage.COM <mailto:owner-xsi(at)Softimage.COM> >> [mailto:owner-xsi(at)Softimage.COM <mailto:owner-xsi(at)Softimage.COM>] On Behalf >> Of Daniele Niero >> >> Hi Andy, >> >> Are you suggesting me to create and use a different Transformation >> object, manipulate it and then put it in the >> output.kineamtics.global.transform? >> Did I understand? >> >> Hi Mathee, >> >> Are you saying the same thing Andy is saying? If not I don't get it. >> I cannot use as output the final channel, for example >> obj.kinematics.global.posx, because this means I have to use 6 output >> instead 1 as so have 6 update instead 1. >> What I'm missing? >> >> Thanks a lot to both of you guys >> Daniele >> > > --- > Unsubscribe? Mail Majordomo(at)Softimage.COM <mailto:Majordomo(at)Softimage.COM> with the following text in body: > unsubscribe xsi > >
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