Hi Philipp,
I guess you allready tried the easy way of exporting the
camera via .xsi and *.fbx (at least for getting an idea of
the required conversion settings or offsets).
IÂm not sure if this helps but Andy Walker has posted
two snippets of valuable info over at the maya(at)highend3d.com
list, here it is pasted in (RE: Converting AngleofView to Focal Length):
-------------------
Yeah, Maya cameras use horizontal angle of views, so using all the
horizontal data, the formula is:
horizontal angle of view = 2 * atand(0.5*film_back_width/focalLength)
The film back width needs to be converted from inches to mm, so
multiply it by 25.4.
e.g. on a 35mm maya camera with an aperture of 1.417 inches:
float $angleOfView = 2 * atand(0.5*((1.417*25.4)/35));
print $angleOfView;
// 54.421607
------------------------
Whoops, i see you want the other way around..
well that should be:
float $angleOfView = 54.421607;
float $horizontalAperture = 1.417*25.4;
float $focalLength = (0.5*$horizontalAperture)/tand($angleOfView/2);
print $focalLength;
// 35mm
------------------------
According to Soren Kurgan Jacobson (same thread):
search the maya mel scripts, if I remember correctly the whole calc is in there
----------------
Hope this helps,
Cheers
tim
----- Original Message -----
From: "Philipp Oeser" <philipp.oeser(at)liga01.de>
To: <XSI(at)Softimage.COM>
Sent: Sunday, December 03, 2006 5:22 AM
Subject: Anyone knows how maya computes filmback translation?
Hi everyone,
I need to convert a XSI camera to Maya and I just cant figure out how maya computes
the translation on the filmback. (their docs say "The values are normalized with
respect to viewing area").
An example:
I have a 0,9802 inch x 0,7352 inch filmback in XSI with an -0,0307 inch horizontal
filmback translation/optical center shift (here it is all in inches)
The cam in Maya (same filmback of 0,9802 inch x 0,7352 inch) seems to match at a
Filmback translate H with a value of about -0.065. (All other settings in Filmback
are standard, no scaling, no filmoffset, no lenssqueeze) (and matching also seems
to be dependent on overscan).
Sorry, it's late at night and I cant get it right...
Any ideas?
Thanx in advance
Philipp
--
Philipp Oeser
Liga_01 Computerfilm GmbH
www.liga01.de
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