Hi Philipp,
I don't have Maya to compare with but in tech-speak a normalized value
is a value between 0 and 1. So if you want to produce a normalized value
from the XSI settings you would take the horizontal offset and divide by
the filmback width like this:
-0.0307 / 0.9802 = -0.0313
Now, based on your guesstimate in Maya of -0.065 it looks like there is
a scale factor of 2 in there so I would expect the equivalent Maya value
to be:
-0.0313 x 2 = -0.0626
(and to go from Maya to XSI just take the normalized value, divide by
two
and finally multiply by the filmback width)
Of course this is just a guess on my part but you should be able to
verify whether this is the case by running a few different settings
through both XSI and Maya.
Hope this helps.
--
Brent
-----Original Message-----
From: owner-xsi(at)Softimage.COM [mailto:owner-xsi(at)Softimage.COM] On Behalf
Of Philipp Oeser
Sent: Sunday, December 03, 2006 4:22 AM
To: XSI(at)Softimage.COM
Subject: Anyone knows how maya computes filmback translation?
Hi everyone,
I need to convert a XSI camera to Maya and I just cant figure out how
maya computes the translation on the filmback. (their docs say "The
values are normalized with respect to viewing area").
An example:
I have a 0,9802 inch x 0,7352 inch filmback in XSI with an -0,0307 inch
horizontal filmback translation/optical center shift (here it is all in
inches)
The cam in Maya (same filmback of 0,9802 inch x 0,7352 inch) seems to
match at a Filmback translate H with a value of about -0.065. (All other
settings in Filmback are standard, no scaling, no filmoffset, no
lenssqueeze) (and matching also seems to be dependent on overscan).
Sorry, it's late at night and I cant get it right...
Any ideas?
Thanx in advance
Philipp
--
Philipp Oeser
Liga_01 Computerfilm GmbH
www.liga01.de
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