I don't really know the answer to your question, so I
appologize if this is wrong, but the cast operator has higher precedence
than the multiply. so it's going to take that 't', cast it to a
long, and do the rest in longs.
I think you wanted to have another set of parenthesis like
(long)(t*3*nbPoints)
in any case,
casting a double to long just like that is not a good idea,
you should add an epsilon to compensate for any numerical
innacuracies.
For example : long id =
(long)(t*3*nbPoints + 0.25);
From:
owner-xsi(at)Softimage.COM [mailto:owner-xsi(at)Softimage.COM] On Behalf Of
Ahmidou Lyazidi
Posted At: Wednesday, June 06, 2007 3:20
PM
Posted To: xsi
Conversation: [SDK]Double to long in c++
?
Subject: [SDK]Double to long in c++ ?
Hi
In
an Operator,we are trying to convert the datas passed by
OperatorContex.GetTime to a long.The thing that is strange is when I log the
value
it seems good, but when I mutiply it with a fixed value it seems to
round it and give me 2 equal values for 2 differant frame
here is the code
and the log:
long oOffset =
oOp.GetParameterValue(L"TimeOffset");
CTime T =
ctxt.GetTime();
Application().LogMessage(L"Current operator Time " +
T.GetAsText());
double t = double(T) + oOffset;
long id = (long) t *
3 * nbPoints;
Application().LogMessage( (CString)t +L"* 3 * "+(CString)
nbPoints +L" = "+(CString)id);
if(t>=startFrame &&
t<=endFrame)
{
Application().LogMessage(L"Reading
Frame "+ (CString) t);
for(long
a=0;a<nbPoints;a++)
{
inPos[a].Set(position[id],position[id+1],position[id+2]);
id += 3;
}
}
//-----------------------------------------
1* 3 * 4 =
11
NextFrame();
// INFO : Current operator Time 00:00:00:02
// INFO :
2* 3 * 4 = 23
// INFO : Reading Frame 2
NextFrame();
// INFO :
Current operator Time 00:00:00:03
// INFO : 3* 3 * 4 = 36
// INFO :
Reading Frame 3
NextFrame();
NextFrame();
// INFO : Current operator
Time 00:00:00:05
// INFO : 5* 3 * 4 = 60
// INFO : Reading Frame 5
Any ideas?
Thanks
A.
