RE: [SDK]Double to long in c++ ?

["Mathieu Leclaire" <mleclair(at)hybride.com>]

Yeah, you are right. But you could still use the round function but adding 0.25 or 0.5 and then casting it to a long will give similar results depending if you want to go in fields or not (as explained by Luc-Eric) so that works too.

 

-----Original Message-----
From: Luc-Eric Rousseau [mailto:lucer(at)Softimage.COM]
Sent: Thursday, June 07, 2007 2:19 PM
To: XSI(at)Softimage.COM
Subject: RE: [SDK]Double to long in c++ ?

 

no, spaces are not significant in c++.

 

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From: owner-xsi(at)Softimage.COM [mailto:owner-xsi(at)Softimage.COM] On Behalf Of Mathieu Leclaire
Posted At: Thursday, June 07, 2007 1:49 PM
Posted To: xsi
Conversation: [SDK]Double to long in c++ ?
Subject: RE: [SDK]Double to long in c++ ?

Wow, my emails really don’t seam to pass through. I’ve been trying to send this reply since yesterday. Let me try one more time…

 

Here’s what I believe is happening:

 

You have a space between (long) and t. So I believe doing long id = (long) t * 3 * nbPoints; is the equivalent of doing long id = (long)(t * 3 * nbPoints); I think this way it converts the result of the entire equation so if t = 1.99, then you get something like 23.88 and then cast it to a long so it'll only keep the 23. But if you remove the space it’ll do the equivalent of long id = (long)(t) * 3 * nbPoints; but if you have 1.99 and cast it to a long, it'll only keep the value 1 which will screw up the result even more. So you can use round(t) and that'll convert a 1.5 to a 2 and a 1.49 to 1. 

 

But I still find it weird that when you log it, it only shows the value 2 even if the real value would be 1.99. But try those and let me know if it helps.

 

I think round is in Math.h so you might need to include that library.