I'd still be careful. You're in uncharted waters there and the buzzards are
circling.
And the metaphors are mixing delightfully.
> -----Original Message-----
> From: owner-xsi(at)Softimage.COM [mailto:owner-xsi(at)Softimage.COM] On
> Behalf Of Alan Jones
> Sent: 20 June 2007 21:48
> To: XSI(at)Softimage.COM
> Subject: Re: Looking up other times in an operator
>
> Just thought I'd let everyone know. Felix's advice worked
> fantastically :-) So now I have my operator with precognition. Thanks
> again for the help.
>
> Cheers,
>
> Alan.
>
> On 6/20/07, Alan Jones <skyphyr(at)gmail.com> wrote:
> > Thanks for the suggestions Felix and Guillaume. Will have a play with
> > it later - charge is to get something for now and so it can work
> > (badly) without it.
> >
> > Cheers,
> >
> > Alan.
> >
> > On 6/20/07, Felix Gebhardt <gebhardt(at)betacarotin.de> wrote:
> > >
> > > Not worky if the kinestate is from an input port as this might pull
> a
> > > whole branch of the DAG if the kinestate is fed from constraints or
> > > other possibly non-deterministic sources and that might have real
> bad
> > > performance issues as caches would be flushed etc. Just imagine you
> > > would have the kinestate constrained to a point on a gigantic,
> fully
> > > rigged character.
> > >
> > > What would be cool is having at least something like:
> > >
> > > if( ks.HasSimpleDeteministicSource() )
> > > ks.Eval( t, funkytime );
> > > else
> > > Log( L"can't work like that" );
> > >
> > > What you could do is re-get the kinestate from it's fullname but
> you are
> > > on you own after that.
> > >
> > > Best,
> > > Felix
> > >
> > > Alan Jones schrieb:
> > > > Hi All,
> > > >
> > > > Are we not able to access other times within an operator?
> > > >
> > > > I've got this
> > > > CTransformation desiredTrans =
> > > > desiredKineState.GetTransform(ctxt.GetTime().GetTime() +
> > > > anticipation);
> > > >
> > > > And it doesn't work. It just gives the current one. Which..
> ummm.. is
> > > > making it suck to be me.
> > > >
> > > > Cheers,
> > > >
> > > > Alan.
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