Re: Hide Component Operator

[Guillaume Laforge <guillaume(at)alamaison.fr>]

>I didn't know whether it was possible to have a dynamic cluster.

Clusters are not dynamic, they are just a cluster of components and your 
operator can read the cluster properties.
Of course, you can add or remove some components from a cluster with 
some XSI commands.

1/2

Guillaume


Alan Jones a écrit :
> The problem is I want the cluster for an output of my operator -
> doesn't need to be an input at all.  - i.e. add and remove polygons to
> it within the operator. Don't need to do any deformation at all.
>
> Cheers,
>
> Alan.
>
> On 10/2/07, Guillaume Laforge <guillaume(at)alamaison.fr> wrote:
>   
> > I think you must add the cluster as an input for your operator.
> >
> > For example if you want to create a custom  deformer operator, add the
> > ActivePrimitive of your mesh as an input / output. As the deformer
> > operator will deal with points, you will need to create a cluster of
> > point and add it as an other input.
> >
> > Then use Cluster.Elements method to only deal with the points return by
> > this method.
> >
> > Hope this help.
> >
> > Cheers
> >
> > Guillaume
> >
> >
> > Alan Jones a écrit :
> >     
> > > Thanks Guillaume,
> > >
> > > Any chance you also know whether it's possible for an operator to
> > > dynamically add to or remove from a cluster? I'll get reading on this
> > > as that would be all the problems sorted.
> > >
> > > Cheers,
> > >
> > > Alan.
> > >
> > > On 10/2/07, Guillaume Laforge <guillaume(at)alamaison.fr> wrote:
> > >
> > >       
> > > > Property > Polygon Cluster Visibility ?
> > > >
> > > > 1/2
> > > >
> > > > Guillaume
> > > >
> > > > Alan Jones a écrit :
> > > >
> > > >         
> > > > > Hi All,
> > > > >
> > > > > I'd like to make an operator which can hide/unhide polygons. Just
> > > > > posting here because I'm guessing this won't be possible.
> > > > >
> > > > > If it is can anyone provide some pointers for where I can start looking?
> > > > >
> > > > > Cheers,
> > > > >
> > > > > Alan.
> > > > > ---
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